\(\left(\sqrt{8}+\sqrt{50}\right).\sqrt{2}=\left(2\sqrt{2}+5\sqrt{2}\right).\sqrt{2}=4+10=14\)
Ta có: \(\left(\sqrt{8}+\sqrt{50}\right)\cdot\sqrt{2}\)
\(=4+10=14\)
\(\left(\sqrt{8}+\sqrt{50}\right)\sqrt{2}=\left(2\sqrt{2}+5\sqrt{2}\right)\sqrt{2}=2.2+5.2=14\)
\(=\left(2\sqrt{2}+5\sqrt{2}\right).\sqrt{2}\)
\(=7\sqrt{2}.\sqrt{2}\)
\(=14\)