Giải
\(\left(-27\right)^{27}=\left(-3^3\right)^{27}=\left(-3\right)^{81}\)
\(\left(-243\right)^{13}=\left(-3^5\right)^{13}=\left(-3\right)^{63}\)
=>\(\left(-27\right)^{27}>\left(-243\right)^{13}\)
Bạn học tốt!^^
So Sánh : \(\left(-32\right)^{27}\)và\(\left(-18\right)^{39}\)
Tìm x :
9 . 27 ≤ \( (\dfrac{1}{3})^2 \) ≤ 27 . 243
a) A=\(\frac{2^{36}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}\)
x-1/13-x-13/15=3x-15/27-4x-27/29
Tìm x
a) 8<\(2^x\le2^9.2^{-5}\) b) 27<\(81^3:3^x< 243\)
1- \(\frac{2}{3}-\frac{2}{9}-\frac{2}{27}-\frac{2}{81}-\frac{2}{243}\)
Tìm giá trị n nguyên dương:
a) \(\dfrac{1}{8}.16^n\)=\(2^n\)
b) \(27< 3^n< 243\)
A=\(\dfrac{2^{30}\cdot5^7+3^{13}\cdot5^{27}}{2^{27}\cdot5^7+2^{10}\cdot5^{27}}\)
M=\(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}\) tại x=7
Chứng minh rằng
a) (81^7-27^9-9^13) chia hết cho 15
