cậu xem lại đề bài xem!
hình như có j đó sai
cậu xem lại đề bài xem!
hình như có j đó sai
M=230.57+213.527/227 . 57+210.527 : 814/1612
A=\(\dfrac{2^{30}\cdot5^7+3^{13}\cdot5^{27}}{2^{27}\cdot5^7+2^{10}\cdot5^{27}}\)
M=\(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}\) tại x=7
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
tinh b=(13/1/4-2/5/17-10/5/8+20/108)*(27/21+711/7)/(1/3/7+10/3):(12/1/3-14/2/7)
tinh b=(13/1/4-2/5/17-10/5/8+20/108)*(27/21+711/7)/(1/3/7+10/3):(12/1/3-14/2/7)
So sánh
a) 3210 và 1615
b) 2711 và 818
c) 536 và 1124
d) 7 . 213 và 216
\(\dfrac{(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}).230.\dfrac{1}{25}+46\dfrac{3}{4}}{(1\dfrac{3}{10}+\dfrac{10}{3}):(12\dfrac{1}{3}-14\dfrac{2}{7})}\)
tính" \(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).203\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
Tinh:
\(A=\dfrac{(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}).203\dfrac{1}{25}+46\dfrac{3}{4}}{(1\dfrac{3}{7}+\dfrac{10}{3}):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(B=\dfrac{\left(81,624:4,8-4.505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)