\(sin\left(2x-10^o\right)=sin3x\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-10^o=3x+k2\pi\\2x-10^o=\pi-3x+k2\pi\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-10^o+k.360^o\\5x=182^o+k.360^o\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-10^o+k.360^o\\x=36,4^o+k.360^o\end{matrix}\right.\)