Câu hỏi của Minh Châu

Question

Rút gọn biểu thức:

3(22 1)(24 1)(28 1)(216 1)

Thu Thao · Accepted Answer

$3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^{16}-1\right)\left(2^{16}+1\right)$

$=2^{32}-1$Câu trả lời: $3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^{16}-1\right)\left(2^{16}+1\right)$

$=2^{32}-1$

Bài 2: Nhân đa thức với đa thức