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3(22 +1)(24 +1)(28 +1)(216 +1)

qwerty · Accepted Answer

$\left(2+1\right)\left(2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^{16}-1\right)\left(2^{16}+1\right)$

$=2^{32}-1$Câu trả lời: $\left(2+1\right)\left(2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)$

$=\left(2^{16}-1\right)\left(2^{16}+1\right)$

$=2^{32}-1$

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