ĐK: \(x\ne-1\)
Rút gọn:
\(\dfrac{10}{x+1}-\dfrac{x^2-1}{x^2+2x+1}\\ =\dfrac{10\left(x+1\right)-\left(x^2-1\right)}{\left(x+1\right)^2}\\ =\dfrac{\left(x+1\right).\left(10-x+1\right)}{\left(x+1\right)^2}=\dfrac{\left(x+1\right).\left(11-x\right)}{\left(x+1\right)^2}\\ =\dfrac{11-x}{x+1}\)