Question

Phân tích thành nhân tử ( thêm bớt hạng tử )

x⁴+x⁵+1

Answer 1

\(x^5+x^4+1\)\(=x^5+x^4+x^3+1-x^3\)

\(=x^3\left(x^2+x+1\right)+\left(1-x\right)\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^3+1-x\right)\)

tik mik nhé !!!

Answer 2

Ta có: \(x^4+x^5+1\)

\(=x^5+x^4+x^3-x^3-x^2-x+x^2+x+1\)

\(=x^3\left(x^2+x+1\right)-x\left(x^2+x+1\right)+\left(x^2+x+1\right)\)

\(=\left(x^3-x+1\right)\left(x^2+x+1\right).\)