Question

phân tích thành nhân tử

a)x²-2x+2y-xy

b) x²+4xy-16+4y²

Answer 1

a,\(x^2-2x+2y-xy\)

\(=\left(x^2-xy\right)+\left(-2x+2y\right)\)

\(=x\left(x-y\right)-2\left(x-y\right)\)

\(=\left(x-2\right)\left(x-y\right)\)

Answer 2

a. \(x^2-2x+2y-xy=\left(x^2-2x\right)-\left(xy-2y\right)=x\left(x-2\right)-y\left(x-2\right)=\left(x-2\right)\left(x-y\right)\)

b. \(x^2+4xy-16+4y^2=\left(x^2+4xy+4y^2\right)-16=\left(x+2y\right)^2-4^2=\left(x+2y-4\right)\left(x+2y+4\right)\)

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Answer 3

a, x(x-2)-y(x-2)

=(x-2)(x-y)

b,x\(^2\)+4xy-16+4y\(^2\)

=(x+2y)\(^2\)-4\(^2\)

=(x+2y-4)(x+2y+4)