Bài đã chữa:
a, x - 9 (x > 0)
= \(\left(\sqrt{x}\right)^2\) - 32
= \(\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)\)
b, x - 5\(\sqrt{x}\) + 4
= x - \(4\sqrt{x}-\sqrt{x}\) +4
= \(\left(\sqrt{x}-1\right)\left(\sqrt{x}-4\right)\)
d: \(=x-1-2\sqrt{x-1}+1-a^2\)
\(=\left(\sqrt{x-1}-1\right)^2-a^2\)
\(=\left(\sqrt{x-1}-1-a\right)\left(\sqrt{x-1}-1+a\right)\)
a: \(=\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)\)
b: \(=\left(\sqrt{x}-1\right)\left(\sqrt{x}-4\right)\)