Question

Phân Tích đa thức thành nhân tử:

Answer 1

\(\left(ax+by\right)^2-\left(ay+bx\right)^2\)
 \(=\left(ax+ay+bx+by\right)\left(ax-ay+by-bx\right)\)
\(=\left(a+b\right)\left(x+y\right)\left(a-b\right)\left(x-y\right)\)
 

Answer 2

\(\left(ax+by\right)^2-\left(ay+bx\right)^2=\left(ax+by-ay-bx\right)\left(ax+by+ay+bx\right)\)

\(=\left[a\left(x-y\right)-b\left(x-y\right)\right].\left[a\left(x+y\right)+b\left(x+y\right)\right]\)

\(=\left(a-b\right)\left(x-y\right)\left(a+b\right)\left(x+y\right)\)

Answer 3

Xin lỗi!
\(\left(ax+by\right)^2-\left(ay+bx\right)^2\)
\(=\left(ax+ay+bx+by\right)\left(ax-ay+bx-by\right)\)
\(=\left(a+b\right)\left(x+y\right)\left(a-b\right)\left(x-y\right)\)

Answer 4

VĐAT

Answer 5

tách ra từ từ

Answer 6

k phải tui