Question

Phân tích đa thức thành nhân tử:
x² - 2x - 4y² + 1
3x² - 12x + 12
12x²y⁵ - 32x³y⁴z + 28x⁴y³
x⁴ + 64
x² - 2xz + 2yz - y²

Answer 1

x²-2x-4y²+1

=(x²-2x+1²)-(2y)²

=(x-1)²-(2y)²

=(x-1-2y)(x-1+2y)

Answer 2

a: \(=\left(x-1\right)^2-4y^2=\left(x-1-2y\right)\left(x-1+2y\right)\)

b: \(=3\left(x^2-4x+4\right)=3\left(x-2\right)^2\)

c: \(=4x^2y^3\left(3y^2-8xyz+7x^2\right)\)

d: \(=x^4+16x^2+64-16x^2=\left(x^2+8\right)^2-16x^2\)

\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)

c: \(=\left(x-y\right)\left(x+y\right)-2z\left(x-y\right)=\left(x-y\right)\left(x+y-2z\right)\)