Question

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phân tích các đa thức sau thành nhân tử :

​1, x²​ - 3x

2, x²​ + 2x +1 - y^​2​

​3, x² - 3x +2

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Answer 1

1) x² - 3x = x(x-3)

2) x² + 2x +1 - y² = (x² + 2x +1) - y² =( x + 1 )² - y²= (x + 1 - y )( x+1+y)

3) x² - 3x + 2 = x² - x - 2x + 2 = (x² - x )- (2x - 2) = x( x - 1) - 2( x - 1 ) = (x -2)(x-1)

Answer 2

1) \(x^2-3x=x\left(x-3\right)\)

2) \(x^2+2x+1-y^2=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)

Answer 3

1)x² -3x=x(x-3)

2) x² +2x+1-y² =(x+1)² -y² =(x+1+y).(x+1-y)

3)x² -3x+2=x² -2x-x+2=(x² -2x)-(x+2)=x(x-2)-(x-2)=(x-2).(x-1)

Answer 4

mấy bài này dễ thế mak ko lm đc~

Answer 5

1) x²-3x = x(x-3)

2) x²+2x+1-y²

= (x²+2x+1) - y²

= (x+1)² - y²

= (x+y+1)(x+1-y)

3) x²-3x+2

=x²-2x-x+2

=(x²-2x)-(x-2)

=x(x-2)-(x-2)

=(x-2)(x-1)

Answer 6

\(x^2-3x=x\left(x-3\right)\)

\(x^2+2x+1-y^2=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)

\(x^2-3x+2=x^2-2x-x+2=\left(x^2-2x\right)-\left(x-2\right)=x\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x-1\right)\)