Câu 14 : \(C=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2}{x-\sqrt{x}}\right):\dfrac{1}{\sqrt{x}-1}\) với x >0 ; x≠0
\(C=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\dfrac{1}{\sqrt{x}-1}\)
\(C=\left(\dfrac{\sqrt{x}.\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}+\dfrac{2}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\dfrac{1}{\sqrt{x}-1}\)
\(C=\dfrac{x+2}{\sqrt{x}\left(\sqrt{x}-1\right)}.\dfrac{\sqrt{x}-1}{1}\)
\(C=\dfrac{x+2}{\sqrt{x}}\)
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Câu 15:
ta có: \(\sqrt{32x}+\sqrt{50x}-2\sqrt{8x}+\sqrt{18x}\)
\(=4\sqrt{2x}+5\sqrt{2x}-4\sqrt{2x}+3\sqrt{2x}\)
\(=8\sqrt{2x}\)