\(\frac{a^2+c^2}{b^2+a^2}=\frac{bc+c^2}{b^2+bc}=\frac{c\left(b+c\right)}{b\left(b+c\right)}=\frac{c}{b}\)
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Bài 7: Tỉ lệ thức
Các câu hỏi tương tự
Cho a,b,c khac 0 va \(\text{a}^2=bc\)
CM \(\dfrac{\text{a}^2+c}{b^2+\text{a}^2}=\dfrac{c}{b}\)
Bài 1: Cho frac{a}{b}frac{c}{d} .CM:
a) frac{a^2}{a^2+b^2}frac{c^2}{c^2+d^2} b) left(frac{a+c}{b+d}right)^2frac{a^2+c^2}{b^2+d^2}
Bài 2: Cho 3 số a,b,cne0, sao cho a^2bc. CM:
a) frac{a^2+c^2}{b^2+a^2}frac{c}{b} b)left(frac{c+2019a}{a+2019b}right)^2frac{c}{b}
Bài 4: Cho a,b,c,d khác 0 sao cho b2ac, c2bd.CM: frac{a^3+b^3+c^3}{b^3+c^3+d^3}frac{a}{d}
Đọc tiếp
Bài 1: Cho \(\frac{a}{b}=\frac{c}{d}\) .CM:
a) \(\frac{a^2}{a^2+b^2}=\frac{c^2}{c^2+d^2}\) b) \(\left(\frac{a+c}{b+d}\right)^2=\frac{a^2+c^2}{b^2+d^2}\)
Bài 2: Cho 3 số a,b,c\(\ne\)0, sao cho a\(^2\)=bc. CM:
a) \(\frac{a^2+c^2}{b^2+a^2}=\frac{c}{b}\) b)\(\left(\frac{c+2019a}{a+2019b}\right)^2=\frac{c}{b}\)
Bài 4: Cho a,b,c,d khác 0 sao cho b2=ac, c2=bd.CM: \(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}=\frac{a}{d}\)
cho các số có hai chữ số ab bc thỏa mãn ab/bc=b/c chứng tỏ a^2+b^2/b^2+c^2=a/c
cho dfrac{a}{b} dfrac{c}{d} cm rằng a) dfrac{a}{a-b} dfrac{c}{c-d} b)dfrac{a}{b} dfrac{a+c}{b+d} c) dfrac{a}{3a+d} dfrac{c}{3c+d} d)dfrac{a.c}{b.d} dfrac{a^2+c^2}{b^2+c^2} e)dfrac{a.b}{c.d} dfrac{a^2-b^2}{c^2-d^2} f)dfrac{a.b}{c.d} dfrac{left(a-bright)^2}{left(c-dright)^2} mn giúp mk vs ạ! thanks
Đọc tiếp
cho \(\dfrac{a}{b}\) =\(\dfrac{c}{d}\) cm rằng
a) \(\dfrac{a}{a-b}\) =\(\dfrac{c}{c-d}\) b)\(\dfrac{a}{b}\) =\(\dfrac{a+c}{b+d}\) c) \(\dfrac{a}{3a+d}\) =\(\dfrac{c}{3c+d}\) d)\(\dfrac{a.c}{b.d}\) =\(\dfrac{a^2+c^2}{b^2+c^2}\) e)\(\dfrac{a.b}{c.d}\) =\(\dfrac{a^2-b^2}{c^2-d^2}\) f)\(\dfrac{a.b}{c.d}\) =\(\dfrac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
mn giúp mk vs ạ! thanks
Cho a;b;c khác 0
Thỏa mãn ab/a+b = bc/b+c = ac/a+c
Tính P= ab^2+ bc^2+ ac^2/ a^3+ b^3+ c^3
Cho ab/bc=b/c.Chứng minh a^2+b^2/c^2+d^2=a/c
Cho a^2+b^2tat ca/c^2+d^2 =ab/cd
va a,b,c,d khac 0
cm a/b=c/d hoac a/b=d/c
Cho \(\dfrac{\text{a}}{b}=\dfrac{c}{d}.CM\)
\(\dfrac{3\text{a}+5b}{3\text{a}-5b}=\dfrac{3c+5d}{3c-5d}\)
\(\left(\dfrac{\text{a}+b}{c+d}\right)^2=\dfrac{\text{a}^2+b^2}{c^2+d^2}\)
Cho đồng thời 3 điều kiện
a + b + c = 1
a2 + b2 + c2 = 1
x/a=y/b=z/c
Cm xy + yz + xz = 0