ĐK : x > y > 0 ( m )
- Theo đề bài ta có hệ phương trình sau :
\(\left\{{}\begin{matrix}2\left(x+y\right)=124\\\left(x+5\right)\left(y+3\right)=xy+255\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x+y=62\\xy+5y+3x+15=xy+255\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x+y=62\\3x+5y=240\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=35\\y=27\end{matrix}\right.\) ( TM )
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