\(1,\\ a,=x^2-3x-4\\ b,=4x^2+4xy+y^2\\ 2,\\ a,\Rightarrow x\left(x^2-13\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x^2=13\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\sqrt{13}\\x=-\sqrt{13}\end{matrix}\right.\\ b,=\left(x+3\right)\left(x^2-3x+9\right)\\ c,=x\left(x+y\right)+\left(x+y\right)=\left(x+y\right)\left(x+1\right)\\ d,=x^2+x+2x+2=\left(x+1\right)\left(x+2\right)\)
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