\(=\lim\limits_{x\rightarrow+\infty}\dfrac{9x^2+7x+1-9x^2}{\sqrt{9x^2+7x+1}+3x}=\lim\limits_{x\rightarrow+\infty}\dfrac{\dfrac{7x}{x}+\dfrac{1}{x}}{\sqrt{\dfrac{9x^2}{x^2}+\dfrac{7x}{x^2}+\dfrac{1}{x^2}}+\dfrac{3x}{x}}=\dfrac{7}{3+3}=\dfrac{7}{6}\)
\(\Rightarrow P=7-6=1\)