Ta có: \(\left(x-\frac{2}{3}\right)\left(x-\frac{1}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\frac{2}{3}=0\\x-\frac{1}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{2}{3}\\x=\frac{1}{2}\end{matrix}\right.\)
Vậy: \(S=\left\{\frac{2}{3};\frac{1}{2}\right\}\)