Theo đề bài : \(\left|\frac{2x+1}{3}\right|=\frac{x+5}{2}\)
TH1: \(\frac{2x+1}{3}=\frac{x+5}{2}\)
=> \(4x+2=3x+15\)
<=> x=13
TH2: \(-\frac{2x+1}{3}=\frac{x+5}{2}\)
=> \(-4x-2=3x+15\)
<=>7x=-17
<=> \(x=-\frac{17}{7}\)
Vậy x\(\in\left\{-\frac{17}{7};13\right\}\)
1. Tìm x ϵ Q sao cho:
a) (2x-3). (x+1) < 0.
b) \(\left(x-\frac{1}{2}\right).\left(x+3\right)\)> 0.
2. Tính:
S=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{999.1001}\)
3. Tìm x: Biết x không thuộc{-2; -5; -10; -17}
\(\frac{3}{\left(x+2\right).\left(x+5\right)}+\frac{5}{\left(x+5\right).\left(x+10\right)}+\frac{7}{\left(x+10\right).\left(x+17\right)}=\frac{x}{\left(x+2\right).\left(x+17\right)}\)
tìm x:
\(2x-\frac{5}{4}=\left(3-\frac{1}{2}\right).\left(x-\frac{1}{3}\right)\)
Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!
\(\left(\frac{1}{2}\right)^5.x=\left(\frac{1}{2}\right)^7\)
\(\left(\frac{3}{7}\right)^2.x=\left(\frac{9}{21}\right)^2\)
Bài tìm x biết :
2x=2
3x=34
7x=77
(-3)x=(-3)5
(-5)x=(-5)4
2x=4
2x=8
2x=16
3x+1=32
5x-1=5
6x+4=610
52x-7=511
(-2)4x+2=64
\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)
\(\left(\frac{5}{6}\right)^{2x}=\left(\frac{5}{6}\right)^5\)
\(\left(\frac{3}{4}\right)^{2x-1}=\left(\frac{3}{4}\right)^{5x-4}\)
\(\left(-\frac{1}{10}\right)^x=\frac{1}{100}\)
\(\left(-\frac{3}{2}\right)^x=\frac{9}{4}\)
\(\left(-\frac{3}{5}\right)^{2x}=\frac{9}{25}\)
\(\left(-\frac{2}{3}\right)^x=-\frac{8}{27}\)
tìm x
a) \(\frac{7^{x+2}+7^{x+1}7^x}{57}=\frac{5^{2x}5^{2x+1}5^{2x+3}}{131}\)
b) \(\left(2x+3\right)^2+\left(3x-2\right)^4=0\)
Tìm x: \(\left|x-5\right|+\frac{\left(x-1\right)\left(x-3\right)}{2}=\frac{\left(x+1\right)^2}{3}-\frac{\left(1-2x\right)^2}{4}\)
Tìm x biết:
a) \(\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)
b) \(\left(\frac{1}{2}x-3\right).\left(\frac{2}{3}x+\frac{1}{2}\right)=0\)
c) \(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5\)
d) \(4x-\left(x+\frac{1}{2}\right)=2x-\left(\frac{1}{2}-5\right)\)
MONG CÁC BN GIÚP ĐỠ MK BÀI NÀY , MK ĐANG CẦN RẤT GẤP 
GIẢI CHI TIẾT RA GIÚP MK VS NHÉ!!!!MK RẤT CẢM ƠN
\(2x-\frac{5}{4}=\left(3-\frac{1}{2}\right).\left(x-\frac{1}{3}\right)\) Tìm x
Các bn ơi giúp mk với
Bài 1: Tìm x :
a ) \(\left|x+\frac{1}{2}\right|=\left|2x+3\right|\)
b) \(\left|x+\frac{1}{5}\right|+\left|x+\frac{2}{5}\right|+\left|x+1\frac{2}{5}\right|=4x\)
giải giúp mk với mai mk kiểm tra rồi
Tìm x:
a)\(3x-\left|2x+1\right|=2\)
b)\(\left|3x-5\right|+\left|2x+3\right|=7\)
c)\(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\left|\left(-3,2\right)+\frac{2}{5}\right|\)
Các bn làm đc câu nào thì làm nha . Help me
1) Tìm x:
a) \(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
b) \(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
CÁC BẠN GIÚP MIK 2 BÀI NÀY NHÉ
