Ôn tập toán 7
Các câu hỏi tương tự
Tìm x: \(\frac{\left(2-3x\right)^2}{3}-\frac{\left(1+2x\right)^2}{2}=\frac{3}{4}-2\left(x-1\right)\left(x+2\right)+x\left(1+x\right)\)
Tìm x: \(\frac{\left(x-3\right)^2}{3}-\frac{\left(2x+1\right)\left(1-3x\right)}{2}=\frac{x\left(x+2\right)}{3}-\left(1+x\right)^2\)
Tìm x : \(\frac{\left(2x+1\right)^2}{2}-\left|x+1\right|=\frac{\left(x-2\right)^2}{3}-3\left(x+4\right)\)
Tìm x: \(\frac{\left(x-2\right)^2}{2}-4\frac{1}{3}\left(x+3\right)^2=\frac{1}{4}\left(x-1\right)\left(x-2\right)-2\left(3x-1\right)\left(2+3x\right)\)
tìm x biết
a, ( 2x - 3 ) ( x + 1 ) <0
b, ( x - \(\frac{1}{2}\) ) ( x + 3) >0
c,\(\frac{3}{\left(x+3\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
biết không thuộc { -2, -5 ,-10 ,-17 }
Tìm x: \(3\left(x-2\right)^2-1\frac{1}{4}\left(1+3x\right)^2=1\frac{1}{3}\left(x-1\right)\left(3-x\right)-1\frac{1}{6}x\left(x-3\right)\)
Tìm x: \(3\left(x-2\right)^2-1\frac{1}{4}\left(1+3x\right)^2=1\frac{1}{3}\left(x-1\right)\left(3+x\right)-1\frac{1}{6}x\left(x-3\right)\)
Tìm x: \(\frac{\left(2x-1\right)^2}{3}-\frac{1}{2}\left(1+3x\right)^2=\frac{1}{3}\left(x-1\right)\left(2-3x\right)\)
Tìm x : \(\frac{\left(x-3\right)^2}{2}-1\frac{1}{3}\left(x+2\right)^2-\frac{5}{4}\left(x-1\right)\left(x+1\right)=1\frac{1}{2}x\left(x-2\right)-x-4\)