\(CTDC:RxOy\)
Do oxi chiếm 74,07%
=>\(\frac{16y}{Rx+16y}.100\%=74,07\%\)
=>\(\frac{16y}{Rx+16y}=0,7407\)
\(M_{RxOy}=108\)
\(\Rightarrow\frac{16y}{108}=0,7407\)
\(\Rightarrow16y=80\)
\(\Rightarrow y=5\)
\(\Rightarrow\) CT có dạng: \(RxO5\)
\(\Rightarrow Rx+16.5=108\)
\(\Rightarrow Rx=28\)
\(x=2\Rightarrow R=14\left(N\right)\)
\(\Rightarrow CTHH:N2O5\)