Question

Làm tính chia \(\left( {6{x^4}{y^3} - 8{x^3}{y^4} + 3{x^2}{y^2}} \right):2x{y^2}\) 

Answer 1

\(\dfrac{6x^4y^3-8x^3y^4+3x^2y^2}{2xy^2}=\dfrac{6x^4y^3}{2xy^2}-\dfrac{8x^3y^4}{2xy^2}+\dfrac{3x^2y^2}{2xy^2}=3x^3y-4x^2y^2+\dfrac{3}{2}x\)