Question

Làm hộ mình=))))))

Answer 1

Hình 2: BG//OD

=>\(\hat{ODG}=\hat{FGB}\) (hai góc đồng vị)

=>\(\hat{ODG}=52^0\)

BO//DG

=>\(\hat{BOD}+\hat{ODG}=180^0\) (hai góc trong cùng phía)

=>\(\hat{BOD}=180^0-52^0=128^0\)

Ta có: \(\hat{BOC}+\hat{BOD}+\hat{COD}=360^0\)

=>\(\hat{BOC}=360^0-162^0-128^0=360^0-290^0=70^0\)

CH//OB

=>\(\hat{HCO}=\hat{COB}\) (hai góc so le trong)

=>\(2x=70^0\)

=>\(x=35^0\)