a) Zn + 2HCl → ZnCl2 + H2
b) \(n_{Zn}=\dfrac{13}{65}=0,2\left(mol\right)\)
Theo PT: \(n_{H_2}=n_{Zn}=0,2\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,2\times22,4=4,48\left(l\right)\)
c) Theo PT: \(n_{HCl}=2n_{Zn}=2\times0,2=0,4\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,4\times36,5=14,6\left(g\right)\)
\(\Rightarrow m_{ddHCl}=\dfrac{14,6}{20\%}=73\left(g\right)\)