Question

Hòa tan 12,25g KClO3 vào 250mL H2O ra dung dịch X. Tính \(C_M\) KClO3.

Answer 1

$m_{KClO_3}= \dfrac{12,25}{122,5} = 0,1(mol)$
$V_{dd\ X} = V_{H_2O} = 0,25(lít)$
$C_{M_{KClO_3}} = \dfrac{0,1}{0,25} = 0,4M$

Answer 2

\(n_{KClO_3}=\dfrac{12,25}{122,5}=0,1\left(mol\right)\Rightarrow C_{M\left(KClO_3\right)}=\dfrac{0,1}{0,25}=0,4M\)