=>(x^2+3)*căn x^2-x+1=x^3+3x^2-4x+1
=>(x^2+3)(x^2-x-120/49)/[căn (x^2-x+1)+13/7=(x+2)(x-2)(x+8/7)
=>x=-8/7 hoặc \(\dfrac{\left(x^2+3\right)\left(x-\dfrac{15}{7}\right)}{\sqrt{x^2-x+1}+\dfrac{13}{7}}=x^2-4\)
=>x=-8/7 hoặc \(x=\dfrac{1\pm\sqrt{3+2\sqrt{5}}}{2}\)