I(x;1/3x+2/3)
Ox: y=0
=>0x+y+0=0
Oy: x=0
=>x+0y+0=0
d(I;Ox)=d(I;Oy)
=>\(\dfrac{\left|0\cdot x+1\left(\dfrac{1}{3}x+\dfrac{2}{3}\right)+0\right|}{\sqrt{0^2+1^2}}=\dfrac{\left|1\cdot x+0\left(\dfrac{1}{3}x+\dfrac{2}{3}\right)+0\right|}{\sqrt{0^2+1^2}}\)
=>|1/3x+2/3|=|x|
=>1/3x+2/3=x hoặc 1/3x+2/3=-x
=>-2/3x=-2/3 hoặc 4/3x=-2/3
=>x=-2/3:4/3=-2/3*3/4=-6/12=-1/2
=>I(-1/2;1/2) và R=1/2
=>I'(-1;1) và R'=1
=>(C'): (x+1)^2+(y-1)^2=1