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Toru
1 tháng 10 2023 lúc 7:38

\(a,\dfrac{15}{16}:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^2\)

\(=\dfrac{15}{16}:\left(-\dfrac{1}{6}\right)^2\)

\(=\dfrac{15}{16}:\dfrac{1}{36}\)

\(=\dfrac{15}{16}\cdot36=\dfrac{135}{4}\)

\(---\)

\(b,\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-\dfrac{15}{17}+\dfrac{2}{3}\)

\(=\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\left(\dfrac{7}{21}+\dfrac{2}{3}\right)-\dfrac{15}{17}\)

\(=1+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)-\dfrac{15}{17}\)

\(=1+1-\dfrac{15}{17}\)

\(=2-\dfrac{15}{17}\)

\(=\dfrac{34}{17}-\dfrac{15}{17}=\dfrac{19}{17}\)

\(---\)

\(c,1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)

\(=\left(1\dfrac{4}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+0,5\)

\(=1+1+0,5\)

\(=2+0,5=2,5\)

\(---\)

\(d,\dfrac{3}{4}\cdot26\dfrac{2}{9}-38\dfrac{2}{9}\cdot\dfrac{3}{4}\)

\(=\dfrac{3}{4}\cdot\left(26\dfrac{2}{9}-38\dfrac{2}{9}\right)\)

\(=\dfrac{3}{4}\cdot\left[26+\dfrac{2}{9}-\left(38+\dfrac{2}{9}\right)\right]\)

\(=\dfrac{3}{4}\cdot\left(26+\dfrac{2}{9}-38-\dfrac{2}{9}\right)\)

\(=\dfrac{3}{4}\cdot\left(-12\right)=-9\)

\(---\)

\(f,-3,75\cdot\left(-7,2\right)+2,8\cdot3,75\)

\(=3,75\cdot7,2+2,8\cdot3,75\)

\(=3,75\cdot\left(7,2+2,8\right)\)

\(=3,75\cdot10=37,5\)

\(---\)

\(g,\left(2\dfrac{1}{2}+0,25\right)-\left(\dfrac{1}{4}-4,25+\dfrac{1}{2}\right)\)

\(=\left(2+\dfrac{1}{2}+\dfrac{1}{4}\right)-\left(\dfrac{1}{4}-\dfrac{17}{4}+\dfrac{1}{2}\right)\)

\(=2+\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}+\dfrac{17}{4}-\dfrac{1}{2}\)

\(=\left(2+\dfrac{17}{4}\right)+\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\left(\dfrac{1}{4}-\dfrac{1}{4}\right)\)

\(=\dfrac{8}{4}+\dfrac{17}{4}=\dfrac{25}{4}\)

#\(Toru\)