Question

Giúp mk vs

\(\left(\dfrac{a+\sqrt{a}}{1+\sqrt{a}}+\dfrac{a}{1-\sqrt{a}}\right)\times\left(\dfrac{a}{2\sqrt{a}}-\dfrac{1}{2}\right)\)

Answer 1

ĐKXĐ: \(a>0 \) \(a\ne 1\)

=\((\sqrt{a} +\frac{a}{1-\sqrt{a} } )(\frac{\sqrt{a} }{2}-\frac{1}{2} )\)

=\(\frac{\sqrt{a} -a+a}{1-\sqrt{a} }\frac{\sqrt{a}-1 }{2}\)

=\(\frac{-\sqrt{a} }{2} \)

Answer 2

\(\left(\dfrac{a+\sqrt{a}}{1+\sqrt{a}}+\dfrac{a}{1-\sqrt{a}}\right).\left(\dfrac{a}{2\sqrt{a}}-\dfrac{1}{2}\right)\)

\(ĐKXĐ:a>0;a\ne1\)

\(=\left(\sqrt{a}+\dfrac{a}{1-\sqrt{a}}\right).\left(\dfrac{\sqrt{a}}{2}-\dfrac{1}{2}\right)\)

\(=\dfrac{\sqrt{a}-a+a}{1-\sqrt{a}}.\dfrac{\sqrt{a}-1}{2}\)

\(=\dfrac{-\sqrt{a}}{2}\)