\(A=-\left(x^2+x+\dfrac{1}{4}\right)+\dfrac{29}{4}=-\left(x+\dfrac{1}{2}\right)^2+\dfrac{29}{4}\le\dfrac{29}{4}\\ A_{max}=\dfrac{29}{4}\Leftrightarrow x=-\dfrac{1}{2}\)
\(A=-\left(x^2-x+\dfrac{1}{4}\right)+\dfrac{29}{4}=-\left(x-\dfrac{1}{2}\right)^2+\dfrac{29}{4}\le\dfrac{29}{4}\)
Dấu "=" xảy ra \(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy \(A_{max}=\dfrac{29}{4}\Leftrightarrow x=\dfrac{1}{2}\)