Question

Giúp mik nka mn 

mik đag cần gấp 

 

Answer 1

\(\dfrac{3}{2x}+\dfrac{3x-3}{2x-1}+\dfrac{2x^2+1}{4x^2-2x}\)

\(=\dfrac{3}{2x}+\dfrac{3x-3}{2x-1}+\dfrac{2x^2+1}{2x\left(2x-1\right)}\)

\(=\dfrac{3\left(2x-1\right)+2x\left(3x-3\right)+2x^2+1}{2x\left(2x-1\right)}\)

\(=\dfrac{6x-3+6x^2-6x+2x^2+1}{2x\left(2x-1\right)}\)

\(=\dfrac{8x^2-4}{2x\left(2x-1\right)}=\dfrac{2\left(4x^2-2\right)}{2x\left(2x-1\right)}=\dfrac{2\left(2x+1\right)\left(2x-1\right)}{2x\left(2x-1\right)}\)

\(=\dfrac{2x+1}{x}\)

Answer 2

\(=\dfrac{6x-3+6x^2-6x+2x^2+1}{2x\left(2x-1\right)}\)

\(=\dfrac{8x^2-2}{2x\left(2x-1\right)}=\dfrac{2\left(2x-1\right)\left(2x+1\right)}{2x\left(2x-1\right)}=\dfrac{2x+1}{x}\)