Question

Giúp em với ạ=((

Answer 1

\(\Leftrightarrow\dfrac{2x+1}{2019}+1+\dfrac{2x+2}{2018}+1+\dfrac{2x+3}{2017}+1+\dfrac{2x+4}{2016}+1=x+1010\)

\(\Leftrightarrow\left(x+1010\right)\left(\dfrac{2}{2019}+\dfrac{2}{2018}+\dfrac{2}{2017}+\dfrac{2}{2016}-1\right)=0\)

=>x+2010=0

hay x=-2010

Answer 2

⇔(x+1010)(22019+22018+22017+22016−1)=0⇔(x+1010)(22019+22018+22017+22016−1)=0

=>x+2010=0

=> x= -2010

Vậy phương trình có tập nghiệm S=(-2010)