\(h,PT\Leftrightarrow3\sqrt[3]{x+2}-2\sqrt[3]{x+2}+2\sqrt[3]{x+2}=3\\ \Leftrightarrow3\sqrt[3]{x+2}=3\Leftrightarrow\sqrt[3]{x+2}=1\\ \Leftrightarrow x+2=1\\ \Leftrightarrow x=-1\)
\(e,PT\Leftrightarrow\sqrt{\left(x-3\right)^2}=\sqrt{\left(\sqrt{3}+1\right)^2}\\ \Leftrightarrow\left|x-3\right|=\sqrt{3}+1\\ \Leftrightarrow\left[{}\begin{matrix}x-3=\sqrt{3}+1\left(x\ge3\right)\\3-x=\sqrt{3}+1\left(x< 3\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{3}+4\left(tm\right)\\x=2-\sqrt{3}\left(tm\right)\end{matrix}\right.\)
\(f,ĐK:x\ge\dfrac{3}{2}\\ PT\Leftrightarrow3x^2-4x=4x^2-12x+9\\ \Leftrightarrow x^2-8x+9=0\\ \Delta=64-36=28\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8-2\sqrt{7}}{2}=4-\sqrt{7}\left(ktm\right)\\x=\dfrac{8+2\sqrt{7}}{2}=4+\sqrt{7}\left(tm\right)\end{matrix}\right.\\ \Leftrightarrow x=4+\sqrt{7}\)
\(g,ĐK:x\ge-\dfrac{5}{7};x< -3\\ PT\Leftrightarrow\dfrac{5x+7}{x+3}=16\\ \Leftrightarrow5x+7=16x+48\\ \Leftrightarrow11x=-41\Leftrightarrow x=-\dfrac{41}{11}\left(tm\right)\)
