ĐKXĐ : \(\left\{{}\begin{matrix}x^2-x\ge0\\3-x\ge0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x\le0\\x\ge1\end{matrix}\right.\\x\le3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x\le0\\1\le x\le3\end{matrix}\right.\)
- PT \(\Leftrightarrow x^2-x=3-x\)
\(\Leftrightarrow x^2=3\)
\(\Leftrightarrow x=\pm\sqrt{3}\) ( TM )
Vậy ...
Giải PT: \(\sqrt{x-1}+\sqrt{x+3}+2\sqrt{\left(x-1\right)\left(x^2-3x+5\right)}=4-2x\)
Giải pt:
a,\(\sqrt{x+\sqrt{2x-1}}+\sqrt{x-\sqrt{2x-1}}=\sqrt{2}\)
b,\(\sqrt{x-3+4\sqrt{x+1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
Giải pt:
a)\(\sqrt{x^2+3x+2}+\sqrt{x^2+6x+5}=\sqrt{2x^2+9x+7}\)
b)\(\sqrt{2x+3}+\sqrt{x+1}=3x+2\sqrt{2x^2+5x+3}-2\)
Giải các pt sau:
1) \(\sqrt{x+3}+2x\sqrt{x+1}=2x+\sqrt{x^2+4x+3}\)
2) \(2\sqrt{x+3}=9x^2-x-4\)
3) \(1+\dfrac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
4) \(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
5) \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=\dfrac{x+3}{2}\)
Giải pt: x2 + x + 24 - 2x\(\sqrt{2x+3}\) = 6\(\sqrt{12-x}\)
Giải PT
a,\(\sqrt{3}x^2-\sqrt{12}=0\) b,\(\sqrt[3]{x+1}=2\)
c,\(\sqrt{4\left(1-x\right)^2}-6=0\) d,\(\sqrt[3]{3-2x}=2\)
1.Giải pt:
a)\(\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+4}=4-2x-x^2\)
b)\(x^2+\left(3-\sqrt{x^2+2}\right)x=1+2\sqrt{x^2+2}\)
c)\(\left(x+1\right)\sqrt{x^2-2x+3}=x^2+1\)
d)
Giải PT: \(\sqrt[3]{24+x}+\sqrt{12-x}=6\)
Giải PT: \(\dfrac{36}{\sqrt{x-2}}+\dfrac{4}{\sqrt{y-1}}=28-4\sqrt{x-2}-\sqrt{y-1}\)
