Bài 3: Phương trình đưa được về dạng ax + b = 0
Các câu hỏi tương tự
Giaỉ các PT:
a) \(\left(x^2+1\right)^2=4\left(2x-1\right)\)
b) x(x+1)(x+2)(x+3)=24
c)\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
d)\(\left(x^2-9\right)^2=12x+1\)
e)\(\left(x-1\right)^5+\left(x+3\right)^5=242\left(x+1\right)\)
Giup mk vs mn
giải phương trình:
\(\left(x^2-9\right)^2=12x+1\)
25 tháng 1 2022 lúc 20:31
4,dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}5,dfrac{2x}{3}+dfrac{2x-1}{6}4-dfrac{x}{3}6,dfrac{x-1}{2}+dfrac{x-1}{4}1-dfrac{2left(x-1right)}{3}
Đọc tiếp
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
Giải pt bằng phương pháp đặt ẩn phụ
a,\(\left(x^2+2x+3\right)\left(x^2+2x+1\right)=3\)
b,\(x\left(x-1\right)\left(x^2-x+1\right)-6=0\)
Giải các phương trình sau :
a) dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4}dfrac{2left(2x+1right)}{7}-5
b) dfrac{3left(x-3right)}{4}+dfrac{4x-10,5}{10}dfrac{3left(x+1right)}{5}+6
c) dfrac{2left(3x+1right)+1}{4}-5dfrac{2left(3x-1right)}{5}-dfrac{3x+2}{10}
d) dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}
Đọc tiếp
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
giải phương trình:
\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
Giải pt sau:
a) \(\left(\dfrac{8}{1.9}+\dfrac{8}{9.17}+\dfrac{8}{17.25}+....+\dfrac{8}{49.57}\right)+2.\left(x-1\right)=\dfrac{2x+7}{3}+\dfrac{5x-8}{4}\)
b) \(\left(x+2\right).\left(x-2\right).\left(x^2-10\right)=72\)
c) (x+3)4+ (x+5)4 = 2
15, giải pt sau.
1,\(\frac{3\left(x+3\right)}{4}+\frac{1}{2}=\frac{5x+9}{3}-\frac{7x-9}{4}\)
2,\(\frac{2x-3}{3}-\frac{x-3}{6}=\frac{4x+3}{5}-17\)
3,\(\frac{5x-1}{6}+\frac{2\left(x+4\right)}{9}=\frac{7x-5}{15}+x-1\)
\(\frac{2x-3}{3}-\frac{x-3}{6}=\frac{4x+3}{5}-17\)
1. ^{x^3+x^2+x+10}
2. left(2x-4right)left(3x+1right)+left(x-2right)^20
3.x^2-5x+60
4. x^2-x-60
5. 2x^2-3x4left(3-2xright)
6. 3left(x-11right)-2left(x+11right)2011
7. left(x-4right)^2-left(x+2right)left(x-6right)0
8. left(x^2-9right)left(x+2right)0
9.left(2x-1right)^24xleft(x-1right)
10. 6left(x+2right)-5x15
Đọc tiếp
1. \(^{x^3+x^2+x+1=0}\)
2. \(\left(2x-4\right)\left(3x+1\right)+\left(x-2\right)^2=0\)
3.\(x^2-5x+6=0\)
4. \(x^2-x-6=0\)
5. \(2x^2-3x=4\left(3-2x\right)\)
6. \(3\left(x-11\right)-2\left(x+11\right)=2011\)
7. \(\left(x-4\right)^2-\left(x+2\right)\left(x-6\right)=0\)
8. \(\left(x^2-9\right)\left(x+2\right)=0\)
9.\(\left(2x-1\right)^2=4x\left(x-1\right)\)
10. \(6\left(x+2\right)-5x=15\)