Question

Giải pt

\(\frac{1}{x+1}+\frac{3}{2x+1}=\frac{8}{x-2}\)

Answer 1

ĐKXĐ: \(x\ne\left\{-1;-\frac{1}{2};2\right\}\)

\(\Leftrightarrow\left(2x+1\right)\left(x-2\right)+3\left(x+1\right)\left(x-2\right)=8\left(x+1\right)\left(2x+1\right)\)

\(\Leftrightarrow11x^2+30x+16=0\Rightarrow\left[{}\begin{matrix}x=-\frac{8}{11}\\x=-2\end{matrix}\right.\)