=>(x^2-x+1)^4+4x^2(x^2-x+1)^2-5x^2=0
=>(x^2-x+1)^4+5x^2(x^2-x+1)^2-x^2(x^2-x+1)^2-5x^2=0
=>(x^2-x+1)^2*[(x^2-x+1)^2+5]-x^2[(x^2-x+1)^2+5]=0
=>(x^2-x+1)^2-x^2=0
=>(x^2-x+1-x)(x^2-x+1+x)=0
=>x^2-2x+1=0
=>x=1
Giải phương trình:
1, \(\left(x^2+x+1\right)\left(x^4+2x^3+7x^2+26x+37\right)=5\left(x+3\right)^3\)
2, \(\left(x+1\right)^3+\left(x+3\right)^3+6\left(x+1\right)\left(x+7\right)\left(x+3\right)=8\left(x+2\right)^3\)
3, \(x^3+\left(x-1\right)^3+3x\left(x-1\right)\left(x^4+x\right)=\left(2x-1\right)^3\)
4, \(\dfrac{\left(x+1\right)^3}{3x+1}+\dfrac{x^3+5x+2}{x^3+2x+1}=x+3\)
5, \(\dfrac{5x^3+x^2+x+1}{4x^2+1}+\dfrac{6\left(4x^2+1\right)}{x^3+x^2+1}=x+7\)
6, \(\left(x^2-4x+1\right)^3+\left(8x-x^2+4\right)^3+\left(x-5\right)^3=125x^3\)
giải bất phương trình \(\left(\sqrt{13}-\sqrt{2x^2-2x+5}-\sqrt{2x^2-4x+4}\right)\left(x^6-x^3+x^2-x+1\right)\ge0\)
Giải phương trình: \(2.\left(x-\sqrt{2x^2+5x-3}\right)=1+x.\left(\sqrt{2x-1}-2\sqrt{x+3}\right)\)
giải phương trình: \(x^2+\left(3-x\right)\sqrt{2x-1}=x\left(3\sqrt{2x^2-5x+2}-\sqrt{x-2}\right)\)
Giải phương trình:
1, \(4\left(2x^2+1\right)+3\left(x^2-2x\right)\sqrt{2x-1}=2\left(x^3+5x\right)\)
2, \(\sqrt{5x^2+4x}-\sqrt{x^2-3x-18}=5\sqrt{x}\)
3, \(\sqrt{5x^2-14x+9}-\sqrt{x^2-x-20}=5\sqrt{x+1}\)
Giải PT
\(\left(x-1\right)\left(x-3\right)\left(x+5\right)\left(x+7\right)=297\)
\(x^4-8x^2+x+12=0\)
\(x^4+5x^3-10x^2+10x+4=0\)
\(\left(6x^2-5x+1\right)\left(x^2-5x+6\right)=4x^2\)
Giải các phương trình sau
a) \(\left(6x^2-5x+1\right)\left(x^2-5x+6\right)=4x^2\)
b) \(\sqrt{2\left(x^4+4\right)}=3x^2-10+6\)
Giải phương trình 1, \(x^2+9x+7=\left(2x+1\right)\sqrt{2x^2+4x+5}\)
2, GPT \(\left(2x+7\right)\sqrt{2x+7}=x^2+9x+7\)
3. GHPT \(\left\{{}\begin{matrix}x^2-2y-1=2\sqrt{5y+8}+\sqrt{7x-1}\\\left(x-y\right)\left(x^2+xy+y^2+3\right)=3\left(x^2+y^2\right)+2\end{matrix}\right.\)
Giải phương trình:
1, \(\left(x+3\right)\left(3x^4+8x^2+12x+21\right)=5\left(x^2+1\right)^3\)
2, \(3\left(x^2+2x-1\right)^2-2\left(x^2+3x-1\right)^2+5x^2=0\)
3, \(\dfrac{x^2+x+1}{x+1}+\dfrac{x^2+2x+2}{x+2}-\dfrac{x^2+3x+3}{x+3}-\dfrac{x^2+4x+4}{x+4}=0\)
4, \(\left(\dfrac{x+6}{x-6}\right)\left(\dfrac{x+4}{x-4}\right)^2+\left(\dfrac{x-6}{x+6}\right)\left(\dfrac{x+9}{x-9}\right)^2=2.\dfrac{x^2+36}{x^2-36}\)
