Question

Giải phương trình \(\left\{{}\begin{matrix}\dfrac{3}{x-2}+\dfrac{2}{y+1}=\dfrac{17}{5}\\\dfrac{2x-2}{x-2}-\dfrac{y+2}{y-1}=\dfrac{26}{5}\end{matrix}\right.\)

Answer 1

Nếu đề là y+1 thì

\(\left\{{}\begin{matrix}\dfrac{3}{x-2}+\dfrac{2}{y+1}=\dfrac{17}{5}\\2+\dfrac{2}{x-2}-1-\dfrac{1}{y+1}=\dfrac{26}{5}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2a+2b=\dfrac{17}{5}\\2a-b=\dfrac{21}{5}\end{matrix}\right.\)

Answer 2

\(\left\{{}\begin{matrix}\dfrac{3}{x-2}+\dfrac{2}{y+1}=\dfrac{17}{5}\\2+\dfrac{2}{x-1}-1-\dfrac{3}{y-1}=\dfrac{26}{5}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{6}{x-2}+\dfrac{4}{y+1}=\dfrac{34}{5}\\\dfrac{6}{x-1}-\dfrac{9}{y-1}=\dfrac{63}{5}\end{matrix}\right.\)

\(\dfrac{4}{y+1}+\dfrac{9}{y-1}=-\dfrac{29}{5}=>y=....\)