Question

Giai phương trình : a ) \(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)

Answer 1

\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)

\(\Leftrightarrow\frac{2x}{3}+\frac{x}{3}-\frac{1}{6}=4-\frac{x}{3}\)

\(\Leftrightarrow\frac{2x}{3}+\frac{x}{3}+\frac{x}{3}=4+\frac{1}{6}\)

\(\Leftrightarrow\frac{4x}{3}=\frac{25}{6}\)

\(\Leftrightarrow x=\frac{25}{8}\)

Answer 2

\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)

<=> 4x+2x-1=24-2x

<=>8x=25

<=> x=25/8

Answer 3

\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3} \)
\(\Leftrightarrow\frac{4x}{6}+\frac{2x-1}{6}=\frac{24}{6}-\frac{2x}{6}\)
\(\Leftrightarrow4x+2x-1=24-2x\)
\(\Leftrightarrow4x+2x+2x=1+24\)
\(\Leftrightarrow8x=25\)
\(\Leftrightarrow x=\frac{25}{8}\)
Vậy tập nghiệm của phương trình là S=\(\left\{\frac{25}{8}\right\}\)