Question

giải bất phương trình
\(\frac{1}{2x-3}\)-\(\frac{3}{x\left(2x-3\right)}\)=\(\frac{5}{x}\)

Answer 1

\(\frac{1}{2x-3}-\frac{3}{x\left(2x-3\right)}=\frac{5}{x}\Leftrightarrow x-3=5\left(2x-3\right)\Leftrightarrow x-3=10x-15\Leftrightarrow-9x=-12\Leftrightarrow x=\frac{4}{3}\)

Answer 2

\(\frac{1}{2x-3}\) - \(\frac{3}{x\left(2x-3\right)}\)=\(\frac{5}{x}\)

ĐKXD :x#0;x#\(\frac{3}{2}\) ( # là khác )

       \(\frac{1}{2x-3}\) - \(\frac{3}{x\left(2x-3\right)}\) =\(\frac{5}{x}\)

<=> \(\frac{1x}{x\left(2x-3\right)}\) - \(\frac{3}{x\left(2x-3\right)}\) = \(\frac{5\left(2x-3\right)}{x\left(2x-3\right)}\)

<=> \(\frac{1x}{x\left(2x-3\right)}\) - \(\frac{3}{x\left(2x-3\right)}\) = \(\frac{10x-15}{x\left(2x-3\right)}\)

=>    1x-3=10x-15

<=> 1x-10x=3-15

<=> -9x      = -12

<=>    x      \(\frac{-12}{-9}\) = \(\frac{4}{3}\)  ( Thỏa mãn đ/k)

Vây x= \(\frac{4}{3}\)

Answer 3

Mày nhìn cái chóa j