ĐKXĐ: \(x\ge0\)
Ta có :
\(5\sqrt{12x}+4\sqrt{3x}+2\sqrt{48x}=14\)
\(\Leftrightarrow10\sqrt{3x}+4\sqrt{3x}+8\sqrt{3x}=14\)
\(\Leftrightarrow\sqrt{3x}\left(10+4+8\right)=14\)
\(\Leftrightarrow22\sqrt{3x}=14\)
\(\Leftrightarrow\sqrt{3x}=\dfrac{7}{11}\)
\(\Leftrightarrow3x=\dfrac{49}{121}\)
\(\Leftrightarrow x=\dfrac{49}{363}\)
Vậy \(x=\dfrac{49}{363}\)