giải này:
A=\(\frac{2x}{x+1}-\frac{x}{x-3}=\frac{8}{x^2-2x-3}\) MTC (x+1)(x-3)
A=\(\frac{2x\left(x-3\right)}{\left(x+1\right)\left(x-3\right)}-\frac{x\left(x+1\right)}{\left(x+1\right)\left(x-3\right)}=\frac{8}{\left(x+1\right)\left(x-3\right)}\)
=>A=2x(x-3)-x(x+1)=8
A=2x2-6x-x2-x=8
A=x2-7x=8
A=x2-7x-8x=0
a-b+c=1+7-8=0
x1=-1
x2=\(-\frac{c}{a}\)=8