\(\left\{{}\begin{matrix}x+y=7\\-x+2y=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-x-y=-7\\-x+2y=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+y=7\\\left[-x-\left(-x\right)\right]+\left(-y-2y\right)=-7-2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+y=7\\-3y=-9\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+y=7\\y=3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+3=7\\y=3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=3\end{matrix}\right.\)
Vậy hệ pt có nghiệm duy nhất \(\left(x;y\right)=\left(4;3\right)\)