b: =>(x-3)(2x+5)+(2x+5)(2x-5)=0
=>(2x+5)(x-3-2x+5)=0
=>(2x+5)(-x+2)=0
=>x=2 hoặc x=-5/2
c: =>3x^2-6x+15-3x^2+30x=0
=>24x+15=0
=>x=-5/8
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Bài 5: Phương trình chứa ẩn ở mẫu
Các câu hỏi tương tự
Giải các PT sau:
a,4x-3/x-5=29/3
b,2x-1/5-3x=2
c,4x-5/x-1=2+x/x-1
d,7/x+2=3/x-5
e,2x+5/2x-x/x+5=0
f,12x+1/11x-4+10x-4/9=20x+17/18
a) 5-4x=3x-9
b) (x-4)(3x+9)=0
c) (x/(x+4))+(12/(x-4))=(4x+48)/(x*x-16)
d) 4-2x=7-x
e) (x+4)(8-4x)=0
f) (x/(x+5))+(11/(x-5))=(x+55)/(x*x-25)
g) ((3x+2)/2) - ((3x+1)/6)= (5/3) +2x
h) 2x-(3-5x)=4(x+3)
i) 3x -6+x=9-x
k) 2t-3+5t= 4t+12
m.n giúp mik ạ ...
giải các bất pt sau:
a, 4x-100
b, 2x+x+12ge0
c, x-5ge3-x
d, 7-3x9-x
đ, 2x-(3-5x)le4left(x+3right)
e, 3x-6+x9-x
f, 2t-3+5tge4t+12
g, 3y-2le2y-3
h,3-4x+24+6xge x+27+3x
i, 5-(6-x)le4left(3-2xright)
k, 5(2x-3)- 4(5x-7)ge19-2left(x+11right)
l, dfrac{2x-5}{3}-dfrac{3x-1}{2} dfrac{3-x}{5}-dfrac{2x-1}{4}
m, 5x-dfrac{3-2x}{2}dfrac{7x-5}{2}+x
n, dfrac{7x-2}{3}-2x 5-dfrac{x-2}{4}
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giải các bất pt sau:
a, 4x-10<0
b, 2x+x+12\(\ge0\)
c, x-5\(\ge3-x\)
d, 7-3x>9-x
đ, 2x-(3-5x)\(\le4\left(x+3\right)\)
e, 3x-6+x<9-x
f, 2t-3+5t\(\ge\)4t+12
g, 3y-2\(\le2y-3\)
h,3-4x+24+6x\(\ge x+27+3x\)
i, 5-(6-x)\(\le4\left(3-2x\right)\)
k, 5(2x-3)- 4(5x-7)\(\ge19-2\left(x+11\right)\)
l, \(\dfrac{2x-5}{3}-\dfrac{3x-1}{2}< \dfrac{3-x}{5}-\dfrac{2x-1}{4}\)
m, \(5x-\dfrac{3-2x}{2}>\dfrac{7x-5}{2}+x\)
n, \(\dfrac{7x-2}{3}-2x< 5-\dfrac{x-2}{4}\)
1. a. 4x-20=0
b. 2x+x+12=0
c. x-5=3-x
d. 7-3x=9-x
2.
a. 7+2x=22-3x
b. 8x-3=5x+12
c. x-12+4x=25+2x-1
d. x+2x+3x-19=3x+5
e. 7-(2x+4)=-(x+4)
f. (x-1)-(2x-1)=9-x
a/4x-3/x-5=29/3
b/2x-1/5-3x=2
c/4x-5/x-1=2+ x/x-1
d/7/x+2=3/x-5
e/2x+5/2x-x/x+5=0
1, giải pt sau
a,\(\frac{9}{x}+2=-6\)
b,\(\frac{7}{x+1}+\frac{-18x}{x\left(x^2+4x+3\right)}=\frac{-4}{x+3}\)
c,\(\frac{3x-1}{x-1}-1=\frac{2x+5}{x+3}+\frac{4}{x^2+2x-3}\)
Giải các phương trình
a) 2x-1/x+3=2x+1/x-3 ;
b) x^2+3/x-2=x+5;
c) 2x(x-6)+3(x-6)=0;
d) (x-1)(2x-4)(3x-9)=0
8 tháng 2 2023 lúc 20:47
4x−2+xx+1x
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Giải pt:
a)\(\dfrac{x+5}{2x-1}-\dfrac{1-2x}{x+5}-2=0\)
b)\(\dfrac{9x-27}{2x-7}-\dfrac{8x-28}{x-3}=0\)
c)\(\dfrac{2x+3}{x-3}-\dfrac{3\left(x-3\right)}{x+3}-2=0\)