Question

Giải hệ phương trình: \(\left\{{}\begin{matrix}x-y\sqrt{2}=6\\2\sqrt{2}x-3y=8\end{matrix}\right.\)

Answer 1

\(\left\{{}\begin{matrix}x-y\sqrt{2}=6\\2\sqrt{2}x-3y=8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2\sqrt{2}x-4y=12\sqrt{2}\\2\sqrt{2}x-3y=8\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}y=8-12\sqrt{2}\\x=-18+8\sqrt{2}\end{matrix}\right.\)