Question

Giải hệ phương trình: \(\left\{{}\begin{matrix}\dfrac{1}{x+y}+\dfrac{1}{x-y}=\dfrac{3}{8}\\\dfrac{1}{x+y}+\dfrac{1}{x-y}=\dfrac{5}{3}\end{matrix}\right.\)

Answer 1

\(\left(x,y\right)\in\varnothing\)