Question

Giải các phương trình sau:

a/ \(\frac{4x-3}{x-5}=\frac{29}{3}\)

b/ \(\frac{4x-5}{x-1}=2+\frac{x}{x-1}\)

c/ \(\frac{2x+5}{2x}-\frac{x}{x+5}=0\)

d/ \(\frac{2x-1}{5-3x}=2\)

e/ \(\frac{7}{x+2}=\frac{3}{x-5}\)

f/ \(\frac{12x+1}{11x-4}+\frac{10x-4}{9}=\frac{20x+17}{18}\)

Answer 1

https://i.imgur.com/tcdqPPM.jpg

Answer 2

f, \(\frac{12x+1}{11x-4}+\frac{10x-4}{9}=\frac{20x+17}{18}\)

\(\Leftrightarrow\) \(\frac{18\left(12x+1\right)}{18\left(11x-4\right)}+\frac{2\left(10x-4\right)\left(11x-4\right)}{18\left(11x-4\right)}=\frac{\left(20x+17\right)\left(11x-4\right)}{18\left(11x-4\right)}\)

\(\Leftrightarrow\) 18(12x + 1) + 2(10x - 4)(11x - 4) = (20x + 17)(11x - 4)

\(\Leftrightarrow\) 216x + 18 + 220x² − 168x + 32 = 220x² + 107x − 68

\(\Leftrightarrow\) 216x + 18 + 220x² − 168x + 32 - 220x² - 107x + 68 = 0

\(\Leftrightarrow\) −59x + 118 = 0

\(\Leftrightarrow\) -59x = -118

\(\Leftrightarrow\) x = 2

Vậy S = {2}

Chúc bạn học tốt!

Answer 3

a) \(\frac{4x-3}{x-5}\)=\(\frac{29}{3}\) (ĐKXĐ:x≠5)

⇔\(\frac{3\left(4x-3\right)}{3\left(x-5\right)}\)=\(\frac{29\left(x-5\right)}{3\left(x-5\right)}\)

⇒12x-9=29x-145

⇔12x-9-29x+145=0

⇔-17x+136=0

⇔-17x=-136

⇔x=8

Vậy tập nghiệm của phương trình đã cho là:S={8}