ĐKXĐ: \(x\ne0\)
\(\frac{\left(x+1\right)\left(x^2-x+1\right)-\left(x-1\right)\left(x^2+x+1\right)}{\left(x^2+x+1\right)\left(x^2-x+1\right)}-\frac{3}{x\left(x^4+x^2+1\right)}=0\)
\(\Leftrightarrow\frac{x^3+1-\left(x^3-1\right)}{x^4+x^2+1}-\frac{3}{x\left(x^4+x^2+1\right)}=0\)
\(\Leftrightarrow2-\frac{3}{x}=0\)
\(\Rightarrow x=\frac{3}{2}\)
Bài 1: Giải các phương trình:
a) \(x+\frac{2x-1}{1-x}=-1\)
b) \(x+\frac{1}{x}=2\)
Bài 2: Giải các phương trình:
a) \(\frac{x}{x-2}=\frac{x-2}{x-3}\)
b) \(\frac{2x-4}{x-1}-\frac{x-3}{x-2}=1\)
c) \(\frac{x+3}{x-1}-\frac{3}{X-1}+\frac{x^2-2}{1-x^2}=0\)
d) \(\frac{2x+1}{x-3}-\frac{3}{x-2}=2\)
Bài 3: Giải các phương trình sau:
a) \(\frac{2x}{x-1}-\frac{x}{x-2}=\frac{x^2}{\left(x-1\right)\left(x-2\right)}\)
b) \(\frac{1}{x+2}\frac{6}{x-1}+\frac{8}{\left(x+2\right)\left(x-1\right)}=0\)
c) \(\frac{x+2}{x+3}-\frac{x+1}{x-1}=\frac{4}{\left(x+3\right)\left(x-1\right)}\)
d) \(\frac{x-1}{x+2}-\frac{x+1}{x-2}=\frac{x-3}{4-x^2}\)
Giải phương trình:
1. \(x^2-3x+2+\left|x-1\right|=0\)
2. \(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)^2-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2\)
GIÚP MK VS!!!
Giải phương trình : \(\left(\frac{x+1}{x-2}\right)^2+\frac{x+1}{x-4}-12\left(\frac{x-2}{x-4}\right)^2=0\)
Giải phương trình: \(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)^2-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2\)
Giải phương trình:
a) \(\frac{4x-8+\left(4-2x\right)}{x^2+1}=0\)
b) \(\frac{x^2\left(x-3\right)}{x}=0\)
c) \(\frac{\left(x+2\right)\left(2x-1\right)-x-2}{x^2-x+1}=0\)
Giải các phương trình sau:
a) \(\left(\frac{x-2}{x-1}\right)^2-5\left(\frac{x+2}{x+1}\right)^2+4\left(\frac{x^2-4}{x^2-1}\right)=1\)
b) \(\left(\frac{x-1}{x}\right)^2+\left(\frac{x-1}{x-2}\right)^2=\frac{40}{9}\)
c) \(x.\frac{4-x}{x+2}.\left(\frac{8-2x}{x+2}\right)=3\)
d) \(\frac{1}{3x-2020}+\frac{1}{4x-2018}+\frac{1}{5x-2017}=\frac{1}{12x-2019}\)
Giải các phương trình sau
e) \(\frac{1}{2}\left(x+1\right)+\frac{1}{4}\left(x+3\right)=3-\frac{1}{3}\left(x+2\right)\)
f)(4-3x)(10x-5)=0
g) (x-3)(2x-1)=(2x-1)(2x+3)
h) 9 - x^2 = 0
Giải phương trình (áp dụng phương pháp đặt ẩn phụ):
a) (x - 1)3 + x3 + (x + 1)3 = (x + 2)3
b) (6x + 7)2(3x + 4)(x + 1) = 6
c) \(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2\)
Giải các phương trình sau
a) \(\frac{1}{x+1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
b) \(\frac{1}{2x-3}-\frac{3}{x\left(2x-3\right)}=\frac{5}{x}\)
c) \(\frac{6}{x-1}-\frac{4}{x-3}=\frac{8}{2x-6}\)
d) \(\frac{3}{\left(x-1\right)\left(x-2\right)}+\frac{2}{\left(x-3\right)\left(x-1\right)}=\frac{1}{\left(x-2\right)\left(x-3\right)}\)
e) \(\frac{1}{x-2}+\frac{5}{x+1}=\frac{3}{2-x}\)
f) \(\frac{5x}{2x+2}+1=-\frac{6}{x+1}\)
g) \(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{4}{x^2-1}\)
h) \(\frac{3x}{x-2}-\frac{x}{x-5}=\frac{3x}{\left(x-2\right)\left(5-x\right)}\)
