\(\Leftrightarrow\dfrac{\left(5x+1\right)\left(x-1\right)-\left(3x-2\right)\left(x+3\right)-2\left(x-1\right)\left(x+3\right)}{\left(x+3\right)\left(x-1\right)}>0\)
\(\Leftrightarrow\dfrac{5x^2-4x-1-3x^2-7x+6-2x^2-4x+6}{\left(x+3\right)\left(x-1\right)}>0\)
\(\Leftrightarrow\dfrac{-15x+12}{\left(x+3\right)\left(x-1\right)}>0\)
\(\Leftrightarrow\dfrac{5x-4}{\left(x+3\right)\left(x-1\right)}< 0\)
=>x<-3 hoặc 4/5<x<1
Đúng 0
Bình luận (0)
